Difference between revisions of ".Mzcw.NzE4Ng"
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− | To apply this to [[unclear | + | To apply this to [[unclear]] suppose it were |
+ | required to find what quantity of progression would | ||
+ | serve 100 men for 4 months [[unclear]] of meat serves | ||
+ | 2 men for 1 month. Then [[unclear]] evident, that | ||
+ | the quantity of meat will be directly in | ||
+ | a compound ratio of the [[unclear]] & of the time: | ||
+ | that is [[formula]] . Therefore | ||
+ | q = 6 x 200 = 12000. And [[unclear]] clearly so; for | ||
+ | if 60 [[image]] serves [[deletion]] [[unclear]] [[/deletion]] two men 1 month; it will require | ||
+ | 50 times 60. [[image]] to serve 100 men for the same | ||
+ | time; that is 3000 [[image]] will serve 100 men | ||
+ | for 1 month. But if 3000 is required for | ||
+ | 1 month; it is evident, that 4 ties as much | ||
+ | [[unclear]] requisite for 4 months, that is 12000th | ||
+ | as before. | ||
+ | |||
+ | 71. A ratio compounded of [[deletion]] [[unclear]] [[/deletion]] two equal ratios is 'called a [[underline]] duplicate ratio. [[/underline]] Thus the ratio of |
Latest revision as of 19:21, 10 August 2018
(14) To apply this to unclear suppose it were required to find what quantity of progression would serve 100 men for 4 months unclear of meat serves 2 men for 1 month. Then unclear evident, that the quantity of meat will be directly in a compound ratio of the unclear & of the time: that is formula . Therefore q = 6 x 200 = 12000. And unclear clearly so; for if 60 image serves deletion unclear /deletion two men 1 month; it will require 50 times 60. image to serve 100 men for the same time; that is 3000 image will serve 100 men for 1 month. But if 3000 is required for 1 month; it is evident, that 4 ties as much unclear requisite for 4 months, that is 12000th as before.
71. A ratio compounded of deletion unclear /deletion two equal ratios is 'called a underline duplicate ratio. /underline Thus the ratio of