Difference between revisions of ".Mzcw.NzIwNg"
From Georgian Papers Programme Transcription Wiki
(Created page with "(24) XII. Questions wherein the") |
|||
| Line 1: | Line 1: | ||
(24) | (24) | ||
| − | XII. Questions wherein the | + | XII. Questions wherein the doctrine |
| + | of Proportion is of [[unclear]] | ||
| + | |||
| + | 82. I. To divide 100 into two parts which | ||
| + | shall be to one another as 5 to 3. | ||
| + | x = the least part. | ||
| + | 100-x=greatest. | ||
| + | x:100-x::3:5. | ||
| + | [[formula]] | ||
| + | Therefore greatest part = 62 1/2. | ||
| + | |||
| + | Or thus let the greatest = 5x | ||
| + | The least [[underline]] = 3x [[/underline]] | ||
| + | 8x = 100 | ||
| + | [[formula]] | ||
| + | Therefore the greatest = 62 1/2. | ||
| + | And the least = 37 1/2. | ||
| + | |||
| + | 83. II. To divide 100 into five parts proportional | ||
| + | to, 2, 3 5; 6, 8. | ||
Latest revision as of 19:43, 11 August 2018
(24)
XII. Questions wherein the doctrine of Proportion is of unclear
82. I. To divide 100 into two parts which shall be to one another as 5 to 3. x = the least part. 100-x=greatest. x:100-x::3:5. formula Therefore greatest part = 62 1/2.
Or thus let the greatest = 5x The least underline = 3x /underline 8x = 100 formula Therefore the greatest = 62 1/2. And the least = 37 1/2.
83. II. To divide 100 into five parts proportional to, 2, 3 5; 6, 8.
