Difference between revisions of ".Mzcw.NzIxMg"
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| − | to each other as | + | to each other as 2000x12, 660x7 & 1255x5, or |
| + | as, 24000, 4620, & 6275. | ||
| + | |||
| + | This problem may be solved like the 2d question | ||
| + | §82, or by several rules of three. For the sum | ||
| + | of the numbers 24000, 4620, & 6275, or 34895 | ||
| + | 34895:1560::2400:x = the share of the first. | ||
| + | Again, 34895:1560::4620:y = share of the second. | ||
| + | And lastly, 34895:1560::6275:z = share of the third | ||
| + | = 1560 - x - y. | ||
| + | |||
| + | 87. Hence questions relating to the rules of | ||
| + | [[underline]] fellowship [[/underline]] in arithmetic may be solved. | ||
| + | |||
| + | 88. VI. Suppose two sorts of silver, the first at | ||
| + | 60d. oz. & the second at 68d. oz: How many ounces | ||
| + | of each sort might to be taken to make up | ||
| + | a mixed mass of 50. oz. at 65d. an ounce? | ||
| + | Let x = number | ||
Revision as of 20:31, 11 August 2018
(27) to each other as 2000x12, 660x7 & 1255x5, or as, 24000, 4620, & 6275.
This problem may be solved like the 2d question §82, or by several rules of three. For the sum of the numbers 24000, 4620, & 6275, or 34895 34895:1560::2400:x = the share of the first. Again, 34895:1560::4620:y = share of the second. And lastly, 34895:1560::6275:z = share of the third = 1560 - x - y.
87. Hence questions relating to the rules of underline fellowship /underline in arithmetic may be solved.
88. VI. Suppose two sorts of silver, the first at 60d. oz. & the second at 68d. oz: How many ounces of each sort might to be taken to make up a mixed mass of 50. oz. at 65d. an ounce? Let x = number
