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(27) to each other as 2000x12, 660x7 & 1255x5, or as, 24000, 4620, & 6275.
This problem may be solved like the 2d question §82, or by several rules of three. For the sum of the numbers 24000, 4620, & 6275, or 34895 34895:1560::2400:x = the share of the first. Again, 34895:1560::4620:y = share of the second. And lastly, 34895:1560::6275:z = share of the third = 1560 - x - y.
87. Hence questions relating to the rules of underline fellowship /underline in arithmetic may be solved.
88. VI. Suppose two sorts of silver, the first at 60d. oz. & the second at 68d. oz: How many ounces of each sort might to be taken to make up a mixed mass of 50. oz. at 65d. an ounce? Let x = number